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Use ICU 2.6.1
Compare characters directly by representing them as int in Unicode.
public static void main(String[] args){
char ch = '\u4e2d';
boolean result = com.ibm.icu.lang.UCharacter.isLetter(ch);
System.out.println(result);
}
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Use ICU 2.6.1
If the comparison is intended to test if a character is a letter, use the following method
com.ibm.icu.lang.UCharacter.IsLetter
(int)
if (ch1 == ch2) {
result = true;
} else {
result = false;
}
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Use ICU 2.6.1
For a locale-sensitive comparison:
-
Convert the character to java.lang.String
-
Use
com.ibm.icu.text.Collator.compare
(java.lang.Object,
java.lang.Object)
String str1="\ud800\udc01";
String str2="\ud800\udc00";
com.ibm.icu.text.Collator collator = com.ibm.icu.text.Collator.getInstance(java.util.Locale.ENGLISH);
int results = collator.compare(str1,str2);
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