Example

public static void main(String[] args){
char ch = '\u4e2d';
boolean result = ( (ch >= 'a' && ch <= 'z') || (ch >= 'A' && ch <= 'Z'));
System.out.println(result);
}
Solution
Use ICU 2.6.1
Compare characters directly by representing them as int in Unicode.

public static void main(String[] args){
char ch = '\u4e2d';
boolean result = com.ibm.icu.lang.UCharacter.isLetter(ch);
System.out.println(result);
}

Solution
Use ICU 2.6.1
If the comparison is intended to test if a character is a letter, use the following method
com.ibm.icu.lang.UCharacter.IsLetter (int)
if (ch1 == ch2) {
result = true;
} else {
result = false;
}
Solution
Use ICU 2.6.1
For a locale-sensitive comparison:
  1. Convert the character to java.lang.String
  2. Use
    com.ibm.icu.text.Collator.compare (java.lang.Object, java.lang.Object)
String str1="\ud800\udc01";
String str2="\ud800\udc00";
com.ibm.icu.text.Collator collator = com.ibm.icu.text.Collator.getInstance(java.util.Locale.ENGLISH); //create collator for specific locale
int results = collator.compare(str1,str2);